X^2+.2x+.01=0

Solution for X^2+.2x+.01=0 equation:

X^2+.2X+.01=0

We add all the numbers together, and all the variables

X^2+.2X+0.01=0

a = 1; b = .2; c = +0.01;
Δ = b2-4ac
Δ = .22-4·1·0.01
Δ = 6.9388939039072E-18
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.2)-\sqrt{6.9388939039072E-18}}{2*1}=\frac{-0.2-\sqrt{6.9388939039072E-18}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.2)+\sqrt{6.9388939039072E-18}}{2*1}=\frac{-0.2+\sqrt{6.9388939039072E-18}}{2}
$